Java Random.nextLong() – Examples
In this tutorial, we will learn about the Java Random.nextLong() method, and learn how to use this method to generate a random long value, with the help of examples.
nextLong()
Random.nextLong() returns the next pseudorandom, uniformly distributed long value from this random number generator’s sequence.
Syntax
The syntax of nextLong() method is
Random.nextLong()
Returns
The method returns long value.
Example 1 – nextLong()
In this example, we will create an object random
of Random
class type. We will call nextLong() on this Random object to get the next long value. We shall print this long value to console.
Java Program
import java.util.Random;
public class Example{
public static void main(String[] args) {
Random random = new Random();
long l = random.nextLong();
System.out.println("Next random long value is : " + l);
}
}
Output
Next random long value is : 5015315584966125576
Output may vary, since the long value is generated randomly.
Example 2 – nextLong()
In this example, we will generate random long values in a for loop using nextLong().
Java Program
import java.util.Random;
public class Example{
public static void main(String[] args) {
Random random = new Random();
for (int i=0; i < 10; i++) {
System.out.println(random.nextLong());
}
}
}
Output
3697628055853821710
3518501742944499700
6568893102887420578
-182089578053327222
-8217330180285651389
-5006204463189382147
-2128146498410395251
-5670315491622791709
-1784447121146279190
-8502179422746111454
Output may vary, since the long value is generated randomly.
Conclusion
In this Java Tutorial, we have learnt the syntax of Java Random.nextLong() method, and also learnt how to use this method with the help of examples.