How to find the smallest of three numbers in Kotlin?

In this tutorial, you shall learn how to find the smallest of given three numbers in Kotlin, with the help of example programs.

Kotlin – Find smallest of three numbers

To find the smallest of given three numbers in Kotlin, we can use comparison operators and conditional statements.

If a, b, and c are given three numbers, the condition to check if a is less than both b and c is

a < b && a < c

If above condition is true, then a is the smallest. If not, b or c is the smallest.

To check the smallest of b and c use the following condition.

b < c

If above condition is true, then b is the smallest. If not, c is the smallest.

Program

In the following program, we read three numbers from user and store them in a, b, and c. We then use the above explanation to write logic for finding the smallest of these three numbers.

Main.kt

fun main() {
    print("Enter first number : ")
    val a = readLine()!!.toDouble()
    print("Enter second number : ")
    val b = readLine()!!.toDouble()
    print("Enter third number : ")
    val c = readLine()!!.toDouble()

    if (a < b && a < c) {
        print("$a is the smallest of $a, $b, and $c")
    } else if (b < c) {
        print("$b is the smallest of $a, $b, and $c")
    } else {
        print("$c is the smallest of $a, $b, and $c")
    }
}

Output #1

Enter first number : 8
Enter second number : 1
Enter third number : 7
1.0 is the smallest of 8.0, 1.0, and 7.0

Output #2

Enter first number : -9
Enter second number : 41
Enter third number : 120
-9.0 is the smallest of -9.0, 41.0, and 120.0

Related tutorials for the above program

• Kotlin Else-If

Conclusion

In this Kotlin Tutorial, we learned how to find the smallest of given three numbers.